Integrand size = 15, antiderivative size = 73 \[ \int \frac {\left (a+b \sqrt {x}\right )^5}{x^7} \, dx=-\frac {a^5}{6 x^6}-\frac {10 a^4 b}{11 x^{11/2}}-\frac {2 a^3 b^2}{x^5}-\frac {20 a^2 b^3}{9 x^{9/2}}-\frac {5 a b^4}{4 x^4}-\frac {2 b^5}{7 x^{7/2}} \]
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Time = 0.02 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {272, 45} \[ \int \frac {\left (a+b \sqrt {x}\right )^5}{x^7} \, dx=-\frac {a^5}{6 x^6}-\frac {10 a^4 b}{11 x^{11/2}}-\frac {2 a^3 b^2}{x^5}-\frac {20 a^2 b^3}{9 x^{9/2}}-\frac {5 a b^4}{4 x^4}-\frac {2 b^5}{7 x^{7/2}} \]
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Rule 45
Rule 272
Rubi steps \begin{align*} \text {integral}& = 2 \text {Subst}\left (\int \frac {(a+b x)^5}{x^{13}} \, dx,x,\sqrt {x}\right ) \\ & = 2 \text {Subst}\left (\int \left (\frac {a^5}{x^{13}}+\frac {5 a^4 b}{x^{12}}+\frac {10 a^3 b^2}{x^{11}}+\frac {10 a^2 b^3}{x^{10}}+\frac {5 a b^4}{x^9}+\frac {b^5}{x^8}\right ) \, dx,x,\sqrt {x}\right ) \\ & = -\frac {a^5}{6 x^6}-\frac {10 a^4 b}{11 x^{11/2}}-\frac {2 a^3 b^2}{x^5}-\frac {20 a^2 b^3}{9 x^{9/2}}-\frac {5 a b^4}{4 x^4}-\frac {2 b^5}{7 x^{7/2}} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 65, normalized size of antiderivative = 0.89 \[ \int \frac {\left (a+b \sqrt {x}\right )^5}{x^7} \, dx=\frac {-462 a^5-2520 a^4 b \sqrt {x}-5544 a^3 b^2 x-6160 a^2 b^3 x^{3/2}-3465 a b^4 x^2-792 b^5 x^{5/2}}{2772 x^6} \]
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Time = 3.58 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.79
method | result | size |
derivativedivides | \(-\frac {a^{5}}{6 x^{6}}-\frac {10 a^{4} b}{11 x^{\frac {11}{2}}}-\frac {2 a^{3} b^{2}}{x^{5}}-\frac {20 a^{2} b^{3}}{9 x^{\frac {9}{2}}}-\frac {5 a \,b^{4}}{4 x^{4}}-\frac {2 b^{5}}{7 x^{\frac {7}{2}}}\) | \(58\) |
default | \(-\frac {a^{5}}{6 x^{6}}-\frac {10 a^{4} b}{11 x^{\frac {11}{2}}}-\frac {2 a^{3} b^{2}}{x^{5}}-\frac {20 a^{2} b^{3}}{9 x^{\frac {9}{2}}}-\frac {5 a \,b^{4}}{4 x^{4}}-\frac {2 b^{5}}{7 x^{\frac {7}{2}}}\) | \(58\) |
trager | \(\frac {\left (-1+x \right ) \left (2 a^{4} x^{5}+24 a^{2} b^{2} x^{5}+15 b^{4} x^{5}+2 a^{4} x^{4}+24 a^{2} x^{4} b^{2}+15 b^{4} x^{4}+2 a^{4} x^{3}+24 a^{2} b^{2} x^{3}+15 b^{4} x^{3}+2 a^{4} x^{2}+24 a^{2} b^{2} x^{2}+15 b^{4} x^{2}+2 a^{4} x +24 a^{2} b^{2} x +2 a^{4}\right ) a}{12 x^{6}}-\frac {2 \left (99 b^{4} x^{2}+770 a^{2} b^{2} x +315 a^{4}\right ) b}{693 x^{\frac {11}{2}}}\) | \(169\) |
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Time = 0.38 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.79 \[ \int \frac {\left (a+b \sqrt {x}\right )^5}{x^7} \, dx=-\frac {3465 \, a b^{4} x^{2} + 5544 \, a^{3} b^{2} x + 462 \, a^{5} + 8 \, {\left (99 \, b^{5} x^{2} + 770 \, a^{2} b^{3} x + 315 \, a^{4} b\right )} \sqrt {x}}{2772 \, x^{6}} \]
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Time = 0.42 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.00 \[ \int \frac {\left (a+b \sqrt {x}\right )^5}{x^7} \, dx=- \frac {a^{5}}{6 x^{6}} - \frac {10 a^{4} b}{11 x^{\frac {11}{2}}} - \frac {2 a^{3} b^{2}}{x^{5}} - \frac {20 a^{2} b^{3}}{9 x^{\frac {9}{2}}} - \frac {5 a b^{4}}{4 x^{4}} - \frac {2 b^{5}}{7 x^{\frac {7}{2}}} \]
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Time = 0.19 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.78 \[ \int \frac {\left (a+b \sqrt {x}\right )^5}{x^7} \, dx=-\frac {792 \, b^{5} x^{\frac {5}{2}} + 3465 \, a b^{4} x^{2} + 6160 \, a^{2} b^{3} x^{\frac {3}{2}} + 5544 \, a^{3} b^{2} x + 2520 \, a^{4} b \sqrt {x} + 462 \, a^{5}}{2772 \, x^{6}} \]
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Time = 0.28 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.78 \[ \int \frac {\left (a+b \sqrt {x}\right )^5}{x^7} \, dx=-\frac {792 \, b^{5} x^{\frac {5}{2}} + 3465 \, a b^{4} x^{2} + 6160 \, a^{2} b^{3} x^{\frac {3}{2}} + 5544 \, a^{3} b^{2} x + 2520 \, a^{4} b \sqrt {x} + 462 \, a^{5}}{2772 \, x^{6}} \]
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Time = 0.05 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.78 \[ \int \frac {\left (a+b \sqrt {x}\right )^5}{x^7} \, dx=-\frac {\frac {a^5}{6}+\frac {2\,b^5\,x^{5/2}}{7}+2\,a^3\,b^2\,x+\frac {5\,a\,b^4\,x^2}{4}+\frac {10\,a^4\,b\,\sqrt {x}}{11}+\frac {20\,a^2\,b^3\,x^{3/2}}{9}}{x^6} \]
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